SAT Randomized Questions - 1 Full Math Practice Test - Answers and Detailed Explanations at the END

(1,1) works since for the first equation, subbing in 1 gives us []

Let the number of voters who voted in favor of the bill be w. According to the problem, 3 times as many voters voted against, so the number against is 3w. The report states that 18,000 more people voted against, so the equation is 3w = w + 18,000. Solving for w gives 9,000, and the number against is 3(9,000) = 27,000.

Rewrite \(f(x)\) in vertex form by completing the square, yielding \(f(x) = 3(x + 4)^2 - 5\). The minimum of \(f(x)\) is at \(x = -4\), so \(g(x) = f(x - 4)\) shifts this to \(x = 0\).

We use the Pythagorean theorem: \( c^2 = 9^2 + 12^2 = 81 + 144 = 225 \). Therefore, \( c = \sqrt{225} = 15 \). The hypotenuse can be written as \( 3\sqrt{25} \), so \( d = 25 \).

Multiplying the first equation by -2 results in \( -2x + 8y = -6 \), which matches the second equation. Thus, the lines are the same, intersecting at infinitely many points.

The decay factor is 0.75 per half-year, which means it decays by 25% every six months. Over a year, this represents a 25% drop, so \(q = 25\).

We use the Pythagorean theorem: \( c^2 = 5^2 + 12^2 = 25 + 144 = 169 \). Therefore, \( c = \sqrt{169} = 13 \). Since the length is already in the form \( \sqrt{169} [/latex}, the value of [latex] d \) is 169.

Rewrite \(f(x)\) in vertex form as \(-3(x - 2)^2 + 7\). The maximum of \(f(x)\) is at \(x = 2\), so \(g(x) = f(x - 6)\) shifts this maximum to \(x = 8\).

To find \( p \): \( 75 = \frac{p}{100} \times 150 \implies p = \frac{75 \times 100}{150} = 50 \). Calculate \( 50 \% \) of \( 75 \): \( \frac{50}{100} \times 75 = 37.5 \).

The change in degrees Fahrenheit is determined by multiplying the temperature increase in kelvins by \( \frac{9}{5} \), since the \( x \) term in the function is being multiplied by this factor. Therefore, the increase in Fahrenheit temperature is \( \frac{9}{5} \times 4.50 = 8.10 \).

Congruent triangles have corresponding angles that are equal. Since \( L \) and \( O \) correspond, angle \( O \) must be 40°.

To find the area in square miles, divide by \(1760^2\): \(23,184,000 / 3,097,600 = 7.48\) square miles.

Start by setting up the equation: \( 32,000 = 4,000(2)^{3r} \). Divide both sides by 4,000 to obtain \( 8 = (2)^{3r} \). Taking the logarithm base 2 of both sides yields \( 3 = 3r \). Therefore, \( r = 1 \).

Both sides simplify to \( 3y - 9 \), which are identical. Therefore, the equation is true for all values of y, leading to infinitely many solutions.

In the function f(x) = -5x + 30, the y-intercept (where x = 0) represents the initial amount of juice Caleb had before he made any popsicles. When x = 0, f(0) = 30, indicating that Caleb started with 30 fluid ounces of juice.

Since \(f(x) = 1.2x\) shows a constant proportional increase, the function is linear and increases with \(x\). Thus, the correct answer is 'Increasing Linear.'

To find the doubling time, set \( g(t) = 2 \cdot g(0) \). Thus, \( 20,000 \cdot (1.05)^{t/300} = 40,000 \). Taking logarithms, isolate \( t \) and convert the answer to hours.

Convert the area to square miles by dividing by \(1760^2\): \(10,240,000 / 3,097,600 = 3.31\) square miles.

To cover the walls twice, double the total area \(w\) to get \(2w\). Since each gallon covers 300 square feet, divide \(2w\) by 300 to get \(P = \frac{w}{150}\).

For the system to have no solution, the slopes must be equal. Converting both equations to slope-intercept form reveals that k must equal -14.

Since \(\frac{c}{d} = 2\), we have \(c = 2d\). Substitute into \(\frac{40c}{qd} = 2\) to get \(\frac{40(2d)}{qd} = 2\). Simplify to \(\frac{80d}{qd} = 2\), cancel \(d\) and solve to find \(q = 40\).

Expanding the right side results in \( 10a - 3 \), which is identical to the left side. Therefore, the equation holds for all values of a, implying infinitely many solutions.

The vertex of the function \( f(x) = \frac{1}{6}(x - 10)^2 + 4 \) occurs at \( (10, 4) \). This represents the minimum height of the basketball. The vertex form of a quadratic function, \( a(x - h)^2 + k \), indicates the vertex as \( (h, k) \). Since \( h = 10 \) and \( k = 4 \), the minimum height is 4 feet above the court.

To find the doubling time, set \( h(t) = 2 \cdot h(0) \) and solve for \( t \): \( 45,000 \cdot (1.04)^{t/200} = 90,000 \). Use logarithms to solve for \( t \) and convert to hours.

To find \( f(0) \), substitute \( 0 \) for \( x \) in the function: \( f(0) = 300(0.2)^0 \). Since any non-zero number raised to the power of \( 0 \) is \( 1 \), the expression becomes \( 300 imes 1 = 300 \).

For a quadratic in the form \( y = ax^2 + bx + c \), the minimum or maximum value of \( y \) occurs at \( x = \frac{-b}{2a} \). Here, \( a = 1 \) and \( b = -10 \), so \( x = \frac{10}{2} = 5 \).

Since \( m(3) = 4096 \), substitute into \( m(x) = 16 \cdot q^x \): \( 16 \cdot q^3 = 4096 \Rightarrow q^3 = 256 \Rightarrow q = 4 \). Now find \( m(\frac{1}{4}) \): \( m(\frac{1}{4}) = 16 \cdot 4^{\frac{1}{4}} = 16 \cdot \sqrt[4]{4} = 16 \cdot \sqrt{2} = 16 \sqrt{2} \).

The decay factor is 0.90 per three months, equating to a 10% drop per quarter. After one year, this approximates to a 34% annual decay rate, so \(m = 34\).

Rewrite \(f(x)\) in vertex form as \(2(x + 2)^2 - 2\). The minimum of \(f(x)\) is at \(x = -2\), so \(g(x) = f(x + 1)\) shifts this to \(x = -3\).

Substitute \( (1, 5) \) into both inequalities. Both inequalities are satisfied.

First, find the measure of angle T in radians: \( \frac{2\pi}{3} + \frac{\pi}{4} = \frac{11\pi}{12} \). Then, convert to degrees by multiplying by \( \frac{180}{\pi} \): \( \frac{11\pi}{12} \cdot \frac{180}{\pi} = 165 \) degrees.

The decay factor is 0.68 every half-year, which means it decays by 32% each six months. This translates to approximately a 55% annual decay rate, so \(p = 55\).

Since \(g(x) = f(x+3) = 5(3)^{x+3} = 5 \cdot 27 \cdot (3)^x = 135(3)^x\), the correct answer is g(x) = 135(3)^x.

Expanding the equation, we obtain \( 2x^2 - 3x + 15 = 15x - 5x^2 \). Rearranging terms, we get \( 7x^2 - 18x + 15 = 0 \). Using the quadratic formula, the sum of the solutions is given by \( -b/a \), where \( a = 7 \) and \( b = -18 \), which yields \( 18/7 \).

Dividing the equation by 16, completing the square, and simplifying gives n = 8.

To cover the walls twice, double the total area \(w\) to get \(2w\). Since each gallon covers 250 square feet, divide \(2w\) by 250 to get \(P = \frac{w}{125}\).

Factor out the greatest common factor, \(5x\), from the expression: \(5x(x^2 + 7x + 12)\). Then factor \(x^2 + 7x + 12\) as \((x + 3)(x + 4)\). The smallest possible value of \(b\) is 3.

Since the function decreases by 45%, it retains 55% of its value at each step. Thus, the multiplier for the decay is 0.55. Therefore, the correct equation is \( q(x) = 14(0.55)^x \).

Since the side lengths of square P are 20 times the side lengths of square Q, the area of square P is \( 20^2 = 400 \) times the area of square Q. Therefore, \( k = 400 \).

Only \( (3, 3) \) is a solution that satisfies both equations.

To find the doubling time, set \( b(t) = 2 \cdot b(0) \) and solve for \( t \): \( 15,000 \cdot (1.06)^{t/100} = 30,000 \). Use logarithms to isolate \( t \) and convert to hours.

Expanding the equation, we obtain \( 2x^2 + 3x - 9 = 4x^2 - 24x \). Rearranging terms, we get \( -2x^2 + 27x - 9 = 0 \). Using the quadratic formula, the sum of the solutions is given by \( -b/a \), where \( a = -2 \) and \( b = 27 \), which yields \( 27/2 \).

Only \( (2, 6) \) satisfies both equations.

The change in degrees Fahrenheit is determined by multiplying the temperature increase in kelvins by \( \frac{9}{5} \), since the \( x \) term in the function is being multiplied by this factor. Therefore, the increase in Fahrenheit temperature is \( \frac{9}{5} \times 5.00 = 9.00 \).