SSAT <- Upper Level SSAT <- 2014 SSAT Free Practice Test Questions - Math Achievement (Quantitative 2) 2014 SSAT Free Practice Test Questions - Math Achievement (Quantitative 2) Share Quiz Get Embed Code Copy the code below to embed this quiz on your website: <iframe src="https://tutorone.ca/practice-test/?embed=true" width="100%" height="800" style="border: none; max-width: 100%;" data-source="tutorone" allowfullscreen></iframe> Copy Code 1234567891011121314151617181920 2014 SSAT Free Practice Test Questions - Math Achievement (Quantitative 2) 1 / 20 The crown in Figure 1 is made up of toothpicks that each have the same length. If each toothpick is 3 meters long and each side is equal to one toothpick, what is the perimeter of the crown in meters? 5 7 10 14 21 The perimeter of a polygon is the sum of the lengths of its sides. Label each of the sides with a value of \(3\) and add. 2 / 20 D is an odd number between 4 and 11. If D is also between 7 and 18, what is the value of D? 5 7 8 9 11 We are looking for an odd integer between \(4\) and \(11\). D must be one of the integers \(5, 7, 9\). Since D is also between \(7\) and \(18\), the only integer that meets both conditions is \(9\). 3 / 20 Gary has a collection of 20 different operas, and his roommate Paul has a collection of 18 different operas. If Paul and Gary have 4 operas in common, how many different operas do they have between them? 18 30 34 36 38 Gary and Paul have a total of \(20 + 18 = 38\) operas put together. Since 4 of them are in common, subtract \(4\) from \(38\), giving \(34\) unique operas. 4 / 20 If \(\frac{1}{6}G = 18\), then \(\frac{1}{3}G\) equals: 6 9 36 54 63 Solve for \(G\) by multiplying both sides by 6: \(G = 18 times 6 = 108\). Substitute \(G = 108\) into the equation \(frac{1}{3}G = frac{1}{3} times 108 = 36\). 5 / 20 A model sailboat floating on the water is attached to a string 1 meter long. If the string is tied to a post on the dock, what is the area of water on which the sailboat can float? \( \pi\) square meters \(2 \pi\) square meters \( \frac{pi}{2}\) square meters \( \pi + 1\) square meters 1 square meter The sailboat can float within a circular area with radius equal to the length of the string, 1 meter. The area of the circle is given by \(A = pi r^2\), where \(r = 1\). The area is \(A = pi\) square meters. 6 / 20 At a party, there are exactly 3 times as many adults as children. Which of the following could be the total number of people at this party? 14 16 20 25 29 Let \(x\) represent the number of children. The number of adults is \(3x\), so the total number of people is \(x + 3x = 4x\). The total must be a multiple of 4. 7 / 20 Using a pair of scissors, which of the following can be made from a 20 cm by 28 cm rectangular sheet of paper with 1 straight cut? Triangle only Square only Rectangle only Triangle and Square only Triangle, Square, and Rectangle A triangle can be made by cutting diagonally. A square can be made by cutting parallel to one side. A smaller rectangle can be made by cutting parallel to any side of the original rectangle. 8 / 20 According to the graph in Figure 3, the average number of students taking the swimming class during the four months of March through June was: 50 55 60 65 70 The number of students in March = \(40\), April = \(60\), May = \(80\), June = \(80\). The average is \(frac{40 + 60 + 80 + 80}{4} = 65\). 9 / 20 For all real numbers \(n\) and \(r\), n ~ r = \( (n-1) - \frac{n}{r}\). What is the value of 6 ~ 2 ? 1 2 3 4 5 Substitute \(n = 6\) and \(r = 2\) into the equation: \(6 clover 2 = (6 - 1) - frac{6}{2} = 5 - 3 = 2\). 10 / 20 Refer to the previous question and note that the same rule applies here. If Q ~ 2=3, then Q= 10 8 6 4 2 Here, you are given n = Q and r = 2. Use the equation given in the definition to set Q$2 equal to 3 and solve for Q: (Q-1) - 2 = 3. First, eliminate the denominator by multiplying both sides by 2:2 (Q- 1) - Q=6. Then, distribute the 2 through the parentheses: 2Q-2 - Q= 6. Third, isolate the Q: Q=8, (B). 11 / 20 Justine bought a comic book at 6 dollars above the cover price. A year later she sold the book for 8 dollars less than she paid. At what price did Justine sell the book? $14 below the cover price $2 below the cover price The cover price $2 above the cover price $14 above the cover price Begin with $6 + cover price - $8 and simplify it. This can be simplified to cover price - $2, which means $2 below the cover price. (B) is correct. 12 / 20 How many fewer boxes of cereal were sold in February than in January? 2 3 20 40 60 Note here that each cube = 20 boxes. February has three cubes less than January, hence 3(20) = 60 boxes less. 13 / 20 The number of boxes sold in March was how many times the number of boxes sold in February? 2 1⅔ 3 40 60 In March, 5 cubes were sold and in February, 3 cubes were sold. Thus, in March, the number of boxes sold was 5/3 = 1⅔ times the number of boxes sold in February. 14 / 20 Team A has 5 times as many losses as it had ties in a season. If Team A won none of its games, which could be the total number of games it played that season? 10 15 18 21 26 Let x = the number of ties for Team A; keep in mind that x is an integer here. Thus, Team A had 5x losses. Adding the losses and ties (there were no wins), the number of games the team played was x + 5x = 6x. Thus, the correct answer choice must be a multiple of 6 (because x is an integer). Only (C), 18, is a multiple of 6. 15 / 20 How many different rectangles are there in Figure 5? 5 9 10 12 Systematically count the different rectangles in the figure. There are 5 basic rectangles. Then, there are 5 rectangles made up of 2 basic rectangles. Next, there is 1 rectangle made up of 3 basic rectangles, and 1 rectangle made up of 4 basic rectangles. In total, there are 5 + 5 + 1 + 1 = 12 different rectangles in the figure. 16 / 20 Which of the following is NOT less than ¼? 2/9 3/14 14/64 19/70 27/125 We are looking for the fraction that is NOT less than ¼, that is, a fraction that is greater than or equal to ¼. (D), 19/70, is correct because it simplifies to a number that is greater than ¼. 17 / 20 In Figure 6, the sides of triangles ABC and FGH, and of squares BCFE and CDGF, are all equal in length. Which of the following is the longest path from A to H? A - B - C - F - H A - B - E - F - H A - C - D - G - H A - B - E - G - H A - C - F - G - H Begin by labeling each side 1. Using the answer choices, count the lengths of the paths: (A) = 4, (B) = 4, (C) = 4, (D) = 5, and (E) = 4. (D), A - B - E - G - H, is the longest path with a length of 5. 18 / 20 5 ⅓ * (5 - x) = 0, then what does x equal? 0 5 14 It cannot be determined from the information given. No long calculation is needed here. In order for a product of numbers to equal 0, at least one of the numbers must equal zero. Since 5 ⅓ is not 0, the other factor, 5 - x, must equal 0. So 5 - x = 0 and x = 5. 19 / 20 Which of the following is closest to 1.08? 12 2.2 1.9 1.1 1 Since 1.08 has 2 places after the decimal point, write each answer choice with 2 places after the decimal point. (A) and (B) are more than 1.00 away from 1.08. (C), 1.90, is more than 0.80 away from 1.08, (D), 1.10, is 0.02 away from 1.08, and (E), 1.00, is 0.08 away from 1.08. 20 / 20 If X is greater than 25, then 5 of X must always be: less than 5 equal to 5 greater than 5 equal to 45 less than 45 Write out the given inequality: X > 25. Next multiply both sides by (or divide both sides by) 5. We now have X/5 > 5, so the answer is greater than 5 (C). Your score is Follow us on socials! LinkedIn Facebook Twitter 0% Restart quiz Send feedback More Quizzes SSAT 011 Math Achievement Section Take Quiz 2015 SSAT Practice Test - Verbal Section + Answers + Explanations Take Quiz 2012 SSAT Practice Test - Verbal Section - 60 Questions Take Quiz 2014 SSAT Verbal Reasoning Practice Test Questions - Official Test with Answers and Explanations Take Quiz 2014 SSAT Free Practice Test - Reading Comprehension Questions Take Quiz SSAT Reading Comprehension Practice Test 2011 Take Quiz 2012 SSAT Practice Test - Quantitative (Math) Section Take Quiz SSAT 2015 Quantitative Practice Test Take Quiz
